미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 解法(해법) > jjalbang6

미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 解法(해법)

페이지 정보

작성일 20-09-30 19:56

본문

학습에 도움이 되길 바랍니다.

솔루션/수학
학습에 도움이 되길 바랍니다. , 미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 솔루션수학솔루션 , calculus james stewart 6th edition solution solutions
calculus,james,stewart,6th,edition,solution,solutions,수학,솔루션
순서

미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 解法(해법)

설명

1 FUNCTIONS AND MODELS
2 LIMITS AND DERIVATIVES
3 DIFFERENTIATION RULES
4 APPLICATIONS OF DIFFERENTIATION
5 INTEGRALS
6 APPLICATIONS OF INTEGRATION
7 TECHNIQUES OF INTEGRATION
8 FURTHER APPLICATIONS OF INTEGRATION
9 DIFFERENTIAL EQUATIONS
10 PARAMETRIC EQUATIONS AND POLAR COORDINATES
11 INFINITE SEQUENCES AND SERIES
12 VECTORS AND THE GEOMETRY OF SPACE
13 VECTOR FUNCTIONS
14 PARTIAL DERIVATIVES
15 MULTIPLE INTEGRALS
16 VECTOR CALCULUS
17 SECOND-ORDER DIFFERENTIAL EQUATIONS

1

FUNCTIONS AND MODELS
www.Civil08.com - The Download Monster

1.1 Four Ways to Represent a Function

In exercises requiring estimations or approximations, your answers may vary slightly from the answers given here. 1. (a) The point (?1, ?2) is on the graph of f , so f (?1) = ?2.

(b) When x = 2, y is about 2.8, so f (2) ? 2.8. (c) f (x) = 2 is equivalent to y = 2. When y = 2, we have x = ?3 and x = 1. (d) Reasonable estimates for x when y = 0 are x = ?2.5 and x = 0.3. (e) The domain of f consists of all x-values on the graph of f . For this function, the domain is ?3 ≤ x ≤ 3, or [?3, 3]. The range of f consists of all y-values on the graph of f . For this function, the range is…(省略)

모든 단원 홀수 번호 解法(해법)입니다.

Download : calculus 6th solution[2].pdf( 71 )

모든 단원 홀수 번호 솔루션입니다.

다.

뒤로가기 jjalbang6

본문