화학반응工學(공학) 2판 해답
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Download : 솔루션 기타 반응공학 solution.pdf
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순서
화학반응工學(공학) 2판 해답
the engineering of chemical reactions , schmidt , 2nd edition
the engineering of chemical reactions , schmidt , 2nd edition
1장~12장 / 화학reaction(반응)공학 2판 해법
Semiconductor Physics and Devices: Basic Principles, 3rd edition Solutions Manual
Chapter 1 Problem Solutions
Chapter 1
Problem Solutions
1.1 (a) fcc: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms Total of 4 atoms per unit cell (b) bcc: 8 corner atoms × 1/8 = 1 atom 1 enclosed atom = 1 atom Total of 2 atoms per unit cell (c) Diamond: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms 4 enclosed atoms = 4 atoms Total of 8 atoms per unit cell 1.2 (a) 4 Ga atoms per unit cell Density = 4 atoms per cell, so atom vol. = 4 Then 4 Ratio =
FG 4πr IJ H3K
3
16 2 r (c) Body-centered cubic lattice 4 d = 4r = a 3 ⇒ a = r 3 Unit cell vol. = a =
3
FG 4πr IJ H 3…(skip)
1장~12장 / 화학반응工學(공학) 2판 해답
the engineering of chemical reactions , schmidt , 2nd edition1장~12장 / 화학반응공학 2판 솔루션 , 화학반응공학 2판 솔루션기타솔루션 , 솔루션
솔루션,기타,솔루션
솔루션/기타
설명
다.